Y=5x^2+20x+26

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Solution for Y=5x^2+20x+26 equation: 



=5Y^2+20Y+26

We move all terms to the left:

-(5Y^2+20Y+26)=0

We get rid of parentheses

-5Y^2-20Y-26=0

a = -5; b = -20; c = -26;
Δ = b2-4ac
Δ = -202-4·(-5)·(-26)
Δ = -120
Delta is less than zero, so there is no solution for the equation

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